by camwill69 on Sat, 25 Aug 2007 4:34 +0000
Gleen,
This is my best attemt at confussing all.
If you use the following formula. Their is not a chance of me using one of the after market recovery points with 2 x 12mm unf bolts attaching them to a 3.14mm Chassis.
Tension on single bolt fT = f ?/ n = (z/2x) (f ?/n) = (z/2x) (f/n)sin (?) = f•y/(2•n•x) were f is the applied force of 3•g = 3•Wcg applied at the center of gravity.
Max load on bolt (assuming tension and shear simply add) is:
LB= 3•Wcg [1/(n+m) + y/(n•2•x)].
My advise is always share the load with either Standard or after market points (x2 or more). Do not just rely on one and always use a saftey lanyard so if something does go wrong the heavy bit is restrained (The hook/recovery point/Shackle).
Regards,
Camwill69